2. What is the molarity of a 25.0 Ml solution of HCL that is titrated to an endpoint using 100 ml of 0.200 M NaOH?
3. If it tookk 200ml of Sr(OH)2 to neutralize 25.0 ml of 0.0500 M HCL what was the molarity of the base??
3. If it tookk 200ml of Sr(OH)2 to neutralize 25.0 ml of 0.0500 M HCL what was the molarity of the base??
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2. (M1)(V1) = (M2)(V2)
(x)(25.0 mL) = (.200 M)(100 mL)
solve for x, x = (.200 M)(100 mL) / (25.0 mL)
x = .800 M HCl
3. (Ma)(Va)(#H's) = (Mb)(Vb)(#OH's)
(0.0500 M) (25.0 ml) (1) = (x) (200 mL) (2)
solve for x, x = (0.0500 M) (25.0 ml) (1) / (200 mL) (2)
x = 0.003 M Sr(OH)2
- Hope I helped!
(x)(25.0 mL) = (.200 M)(100 mL)
solve for x, x = (.200 M)(100 mL) / (25.0 mL)
x = .800 M HCl
3. (Ma)(Va)(#H's) = (Mb)(Vb)(#OH's)
(0.0500 M) (25.0 ml) (1) = (x) (200 mL) (2)
solve for x, x = (0.0500 M) (25.0 ml) (1) / (200 mL) (2)
x = 0.003 M Sr(OH)2
- Hope I helped!