I keep getting this wrong and followed the formula.
If 6.67 moles of an ideal gas has a pressure of 2.01 atm and a volume of 94.31L what is the temperature of the sample in degrees Celsius? I got 2.33 and it was wrong?
If 6.67 moles of an ideal gas has a pressure of 2.01 atm and a volume of 94.31L what is the temperature of the sample in degrees Celsius? I got 2.33 and it was wrong?
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PV = nRT
(2.01) (94.31) = (6.67) (0.08206) (T)
T = 346. K
74 C
(2.01) (94.31) = (6.67) (0.08206) (T)
T = 346. K
74 C
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From P V = n R T
2,01 atm * 94,31 L = 6,67 mol * 0,08206 L atm /(mol K) * T
T= 346,59 K = 73,44 C
2,01 atm * 94,31 L = 6,67 mol * 0,08206 L atm /(mol K) * T
T= 346,59 K = 73,44 C