Which statement is true

A researcher randomly surveyed seniors at a high school and asked how many books they read in the past year. The table shows the results.

Males
n1=147
x(x-bar)1=6.6
s1=1.5

Females
n2=112
x(x-bar)2=9.8
s2=2.1

Which statement is true?

There is a 95% probability that female seniors at this high school read between 2.74 and 3.66 more books per year than male seniors at this high school.
There is a 95% probability that male seniors at this high school read between 2.74 and 3.66 more books per year than female seniors at this high school.
There is a 95% probability that female seniors at this high school read between 3.09 and 3.31 more books per year than male seniors at this high school.
There is a 95% probability that male seniors at this high school read between 3.09 and 3.31 more books per year than female seniors at this high school.

using separate variances, the std dev of the difference in means is
sqrt(1.5^2/147 + 2.1^2/112)=.2338
for 95% prob, use 1.96 std dev, or 1.96(.2338)=.4582

avg difference (female-male)=3.2
So 3.2 +/- .4582 gives an interval of 2.74 to 3.66.

So the 1st choice is correct.

I think the third statement is true.