I have no idea what a DERIVATIVE is. I'm being asked to "find the definition of the derivative".
They give me F(X)=#
Do I find F'(X)=#?
How?
Can you do some examples like
F(X)=-5 to find F'(X)?
and
F(X)=3x-7 to find F'(X)?
and
F(X)=2-3x^2 to find F'(X)
Then F'(1), then F'(2), then F'(3)
and
F(X)=5x/3+x to find F'(X)
I know the answers. The answers aren't important. I just want to know the steps in doing it. I'm really terrible in Math and I am completely lost. Please help! Explain it like I'm 5. Thank you.
They give me F(X)=#
Do I find F'(X)=#?
How?
Can you do some examples like
F(X)=-5 to find F'(X)?
and
F(X)=3x-7 to find F'(X)?
and
F(X)=2-3x^2 to find F'(X)
Then F'(1), then F'(2), then F'(3)
and
F(X)=5x/3+x to find F'(X)
I know the answers. The answers aren't important. I just want to know the steps in doing it. I'm really terrible in Math and I am completely lost. Please help! Explain it like I'm 5. Thank you.
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I'll do the middle two and leave the outer two probelms for you to try. The definition of the derivative may be expressed as
lim [ f(x+h) - f(x)]/h as h goes to 0
So, in writing the calculation of the deriviate I'll write "lim" which implies I'm writing the limit as h approaches 0.
2. f(x) = 3x - 7 and f'(x) = ?
lim [ 3(x+h) - 7 - (3x-7)] / h = lim [ 3x + 3h - 7 - 3x + 7] / h
= lim [ 3h] / h
= lim 3
= 3
3. f(x) = 2 - 3 x^2 and f'(x) = ?
lim [ (2 - 3 (x+h)^2) - (2 - 3x^2) ] / h = lim [ 2 - 3 (x^2 + 2xh + h^2) - 2 + 3x^2] / h
= lim [2 - 3x^2 - 6xh - 3h^2 - 2 + 3x^2] / h
= lim [ - 6xh - 3h^2] / h
= lim [ h ( -6x - 3h)] / h
= lim [-6x - 3h]
= -6x
Since f'(x) = -6x, you may find the values of f'(1) = -6(1) = -6, f'(2) = -12, f'(3) = -18.
lim [ f(x+h) - f(x)]/h as h goes to 0
So, in writing the calculation of the deriviate I'll write "lim" which implies I'm writing the limit as h approaches 0.
2. f(x) = 3x - 7 and f'(x) = ?
lim [ 3(x+h) - 7 - (3x-7)] / h = lim [ 3x + 3h - 7 - 3x + 7] / h
= lim [ 3h] / h
= lim 3
= 3
3. f(x) = 2 - 3 x^2 and f'(x) = ?
lim [ (2 - 3 (x+h)^2) - (2 - 3x^2) ] / h = lim [ 2 - 3 (x^2 + 2xh + h^2) - 2 + 3x^2] / h
= lim [2 - 3x^2 - 6xh - 3h^2 - 2 + 3x^2] / h
= lim [ - 6xh - 3h^2] / h
= lim [ h ( -6x - 3h)] / h
= lim [-6x - 3h]
= -6x
Since f'(x) = -6x, you may find the values of f'(1) = -6(1) = -6, f'(2) = -12, f'(3) = -18.