Help me translate this word problem? Giving 5 stars

1) The length of a rectangle is three times the width. The area is 108 cm^2. Find the dimensions of the rectangle.

2) A square field had 3 m added to its length and 2m added to its width. The field then had an area of 90 m^2. Find the length of a side of the original field.

3)The length of a rectangular park is 2 km less than twice the width. The area is 9 km^2. Find the dimensions of the park


PS: Just translate the word problem into equation, you don't have to solve it.

1.) Length = L
     Width = W
     Area, A = 108 sq. cm.

L = 3W

(3W)W = A
3W² = 108
W² =108 / 3
W² = 36
W = √36
W = ± 6

Feasible Domain: W > 0

Since W = - 6 is not in the feasible domain,

W = 6

and

L = 3(6)
L = 18

Dimensions: 6 cm. x 18 cm.
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2.) Original Length = L
     Area, A = 90 sq. m.

(L + 3)(L + 2) = A
L² + 5L + 6 = 90
L² + 5L + 6 - 90 = 0
L² + 5L - 84 = 0
(L + 12)(L - 7) = 0

If the product of two factors equals zero, then one or both factors equal zero.

If L + 12 = 0,
L = - 12

If L - 7 = 0,
L = 7

Feasible Domain: L > 0

Since L = - 12 is not in the feasible domain,

Original Length of Side = 7 m.
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3.) Width = W
     Length = L
     Area, A = 9 sq. km.

L = 2W - 2

LW = A

(2W - 2)W = 9
2W² - 2W = 9
2(W² - W) = 9
W² - W = 9/2
W² - W = 4.5
W² - W + 0.25 = 4.5 + 0.25
(W - 0.5)² = 4.75
W - 0.5 = √4.75
W - 0.5 = ± 2.18
W = 0.5 ± 2.18

If W = 0.5 + 2.18,
W = 2.68

If W = 0.5 - 2.18,
W = - 2.82

Feasible Domain: W > 0

Since W = - 2.82 is not in the feasible domain,

W = 2.68

and

L = 2(2.68) - 2
L = 5.36 - 2
L = 3.36

Dimensions: 2.68 km. x 3.36 km.
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1) 3w^2 = 108
w^2=36
w = 6
width = 6 cm
length = 18 cm

2) (w+3)(w+2)=90
w^2+5w-84 = 0
(w-7)(w+12) = 0
original length = 7 m

3)w(2w-2) = 9
2w^2-2w-9 = 0

1)
l=3w
lw=108

2)
(l+3)(w+2)=90

3)
l+2=2w
lw=9