I need help with this math problem 1-xy-20x^2y^2. How do I solve it? Thank You.
-
It's an expression, not an equation, or a problem. It isn't subject to being solved.
It can perhaps be factored or simplified. Like, noticing that it's a quadratic in xy, you can go:
1 - xy - 20x²y² = 1 - xy - 20(xy)² = (1 - 5xy)(1 + 4xy)
Or you can look for its zeroes:
1 - xy - 20x²y² = 0
(1 - 5xy)(1 + 4xy) = 0
xy = ⅕, -¼
Is any of that what you were looking for?
It can perhaps be factored or simplified. Like, noticing that it's a quadratic in xy, you can go:
1 - xy - 20x²y² = 1 - xy - 20(xy)² = (1 - 5xy)(1 + 4xy)
Or you can look for its zeroes:
1 - xy - 20x²y² = 0
(1 - 5xy)(1 + 4xy) = 0
xy = ⅕, -¼
Is any of that what you were looking for?
-
- (4*x*y + 1)*(5*x*y - 1) = 0
4*x*y = - 1
5*x*y = 1
No solution!
4*x*y = - 1
5*x*y = 1
No solution!
-
What are you trying to solve?
The zeros?
The zeros?
-
Xy=1 and xy=1/20
-
Google it