Find the exact value of the indicated trigonometric function of theta.
Favorites|Homepage
Subscriptions | sitemap
HOME > > Find the exact value of the indicated trigonometric function of theta.

Find the exact value of the indicated trigonometric function of theta.

[From: ] [author: ] [Date: 12-04-27] [Hit: ]
......
cot theta= -5/4, cos theta<0 find csc theta

the answer is: sqrt41/4

-
On the coordinate plane sin θ= y/r and cos θ= x/r
the tan θ= y/x
The cotθ = 1/tanθ = x/y= -5/4
since to cos θ <1 and the cot θ < 1 (both negative ) because x = -4 and y=5
we must be in QII and the sin θ and csc θ are both positive in QII

x^2 + y^2 = r^2

(-4)^2 + (5)^2 = r^2
16 + 25 = r^2
41 = r^2
r = √41

sin θ = y/r so the csc θ = r/y = √41/4
1
keywords: of,indicated,value,function,theta,exact,Find,trigonometric,the,Find the exact value of the indicated trigonometric function of theta.
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .