A loop circuit has a resistance of R1 and a current of 1.8 A. The current is reduced to 1.6 A when an additional 4.2 ohms resistor is added in series with R1. What is the value of R1? Assume the inter-
nal resistance of the source of emf is zero.
nal resistance of the source of emf is zero.
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You have two unknowns, emf and R1. So you'll need two equations, which are given via two different scenarios. The first scenario says:
V = (1.8 A)R1
The second says:
V = (1.6 A)(R1 + 4.2)
Plug equation 1 into equation 1:
1.8R1 = 1.6R1 + 6.72
0.2R1 = 6.72
R1 = 33.6 Ω
V = (1.8 A)R1
The second says:
V = (1.6 A)(R1 + 4.2)
Plug equation 1 into equation 1:
1.8R1 = 1.6R1 + 6.72
0.2R1 = 6.72
R1 = 33.6 Ω