I need some help with steps
If [x^2] / [64] + [y^2] / [49] = 1 and y(2) = 6.77772 find y'(2) by implicit differentiation.
If [x^2] / [64] + [y^2] / [49] = 1 and y(2) = 6.77772 find y'(2) by implicit differentiation.
-
Starting from [x^2] / [64] + [y^2] / [49] = 1, we derive all elements with respect to x:
2x / 64 + (2y/49) dy/dx = 0.
therefore:
dy/dx = y'(x) = -49x/(64y).
y'(2) = -2*49/(64 * 6.77772) = -0.4334
2x / 64 + (2y/49) dy/dx = 0.
therefore:
dy/dx = y'(x) = -49x/(64y).
y'(2) = -2*49/(64 * 6.77772) = -0.4334