What is the molality of 18 g of decane in 53.5g of Chloroform

Decane is C10H22. 1 mole of it = 10(12.0) + 22(1.0) = 142 g

Moles of decane = 18 g x 1 mol / 142 g = 0.127 mol

molality = mol/kg = 0.127 mol / 0.0535 kg = 2.37 m