A) 3x^2 + 24
B) 6x + 20
C) x
D) 0
B) 6x + 20
C) x
D) 0
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Well the first derivative = 3x^2 + 20x
so that would make the second derivative = 6x +20 so B.
so that would make the second derivative = 6x +20 so B.
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The first derivative would be 3x^2 + 20x; the second is 6x + 20. B
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f(x)=x^3+10x^2-12,
f'(x)=3x^2+20x,
f''(x)=6x+20.
Answer: B. 6x+20.
f'(x)=3x^2+20x,
f''(x)=6x+20.
Answer: B. 6x+20.