Factor 9x^2 - 64 completely. help?
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difference of two squares:
9x^2 - 64 = (3x-8)(3x+8)
(9x^2 + 24x - 24x -64, and then the 24x's cancel eachother out)
9x^2 - 64 = (3x-8)(3x+8)
(9x^2 + 24x - 24x -64, and then the 24x's cancel eachother out)
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Since 9, x^2, and 64 are all perfect squares, we can take the square root to factor the function.
The factored form is:
(3x-8)(3x+8)
The factored form is:
(3x-8)(3x+8)
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(3x+8)(3x-8)
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(3x+8)(3x-8)