If y= Acoskt + Bsinkt where A, B, and k are constants, show that y"+k^2y=0
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If y= Acoskt + Bsinkt where A, B, and k are constants, show that y"+k^2y=0

[From: ] [author: ] [Date: 12-04-23] [Hit: ]
please and thank you-1.2. plug in function of y and y in the function y+k^2y=0.(-Aksinkt + Bkcoskt) + k^(2(Acoskt + Bsinkt))=0,3. if everything in the left cancels out,......
i did this

y"= -Aksinkt + Bkcoskt

=y" + k^2y
=-Aksinkt + Bkcoskt + k^2(Acoskt + Bsinkt)
=-Aksinkt + Bkcoskt + Ak^2coskt + Bk^2sinkt

is this right, how do i do the rest? please and thank you

-
1. Find y''
2. plug in function of y'' and y in the function y"+k^2y=0.
(-Aksinkt + Bkcoskt) + k^(2(Acoskt + Bsinkt))=0, assuming you did y'' correctly
3. if everything in the left cancels out, then you did it right
1
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