Solve Each Log Equation for x.
(1) logsub5(x) = e
(2) lnx = -e
(1) logsub5(x) = e
(2) lnx = -e
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Solve Each Log Equation for x.
[..] => base
(1) log[5](x) = e
change to exponential form
x = 5^e
(2) lnx = -e
x = e^(-e) = 1/e^e
[..] => base
(1) log[5](x) = e
change to exponential form
x = 5^e
(2) lnx = -e
x = e^(-e) = 1/e^e