9th grade Algebra.Square roots. I don't understand. Best answer gets 10 points!
[From: ] [author: ] [Date: 12-04-12] [Hit: ]
p=algebr…oh for the last one, that was unnecessary spacing... didnt realize it was rad. 3 I thought it was rad.......
And √4 is just 2, so √4 x √6 = 2√6
Answer: 2√6
(3 + √7)^2 = 3^2 + 2(3)(√7) + (√7)^2 = 9 + 6√7 + 7 = 16 + 6√7
Answer: 16 + 6√7
√3 (5√3 - 2√6) =
√3(5√3) - √3(2√6) =
5√(3 x 3) - 2√(3 x 6) =
5√9 - 2√18 =
5√9 - 2√(9 x 2) =
5√9 - 2(√9)(√2) =
5(3) - 2(3)(√2) =
15 - 6√2
Answer: 15 - 6√2
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√ 24
√ 4 x 6
2 √ 6
(3 + √ 7) (3 + √ 7) = 9 + 6√7 + 7 = 16 + 6√7
√ (15 √ 3 - 6 √ 6)
3i √ 10
I dunno about the last one. use this : http://mathway.com/problem.aspx?p=algebr…
oh for the last one, that was unnecessary spacing... didnt realize it was rad. 3 I thought it was rad. of whatever 3 distributes and gets.
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prob 1)
you are allowed to multiply things that are under the radical sign
√3 x √ 8 = √24 = √4 x √ 6 = 2√6
prob 2
FOIL it out
(3 + √7)(3 + √7) = 9 + 3√7 + 3√7 + 7 = 16 + 6√7
prob 3
distribute the √3 through the parentheses
√3(5√3 - 2√6) = 5√9 - 2 √18 = 5(3) - 2(3)√2 = 15 - 6√2
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Multiply the numbers inside the radical sign: √3 x √8 = √(3 x 8) = √24 = √(4 x 6) = √4 x √ 6 = 2√6
(3 + √7)^2: FOIL just like you would do with any other binomial: 9 + 6√7 + 7 = 16 + 6√7
√3(5√3 - 2√6): Distribute √3:
(5√3 x √3) - (2√6 x √3)
5√9 - 2√18; √9 = 3, √18 = 3√2
(5 x 3) - (2 x 3√2)
15 - 6√2
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➊ √ ̅3̅ ̅ √ ̅8̅ = √ ̅3̅·̅8̅ ̅ = √ ̅2̅4̅ ̅ ← used the rule √ ̅a̅ √ ̅b̅ = √ ̅a̅b̅
= √ ̅4̅·̅6̅
= √ ̅4̅ ̅ √ ̅6̅
= 2√ ̅6̅
➋ (3+√ ̅7̅ )² ← this is like (a+b)²
= 3² + 2·3√ ̅7̅ + (√ ̅7̅ )² ← used rule (a+b)² = a²+2ab+b²
= 9 + 6√ ̅7̅ + 7 ← used rule (√ ̅a̅ )² = a
= 16 + 6√ ̅7̅
➌ √ ̅3̅ (5√ ̅3̅ - 2√ ̅6̅ ) ← this is like a(b+c)
keywords: Algebra,th,grade,Best,roots,Square,gets,039,understand,10,answer,don,points,9th grade Algebra.Square roots. I don't understand. Best answer gets 10 points!