Find the equation of the hyperbola with foci (0,25) and (0, -25) whose transverse axis has length 14
thanks :)
thanks :)
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c² -a²=b²
a= center-vertices, c= center-focii
2a = 14 , a=7
c= 25
plug a and c in, solve for b
since the hyperbola has vertical transverse axis, the form is
y²/a² - x²/b² =1
a= center-vertices, c= center-focii
2a = 14 , a=7
c= 25
plug a and c in, solve for b
since the hyperbola has vertical transverse axis, the form is
y²/a² - x²/b² =1