A circle that has center at (4,6) and a point on the circle (16,11)?
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use distance formula:
r² = (4 - 16)² + (6 - 11)²
= 169
then plug into standard form:
(x - 4)² + (y - 6)² = 169
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r² = (4 - 16)² + (6 - 11)²
= 169
then plug into standard form:
(x - 4)² + (y - 6)² = 169
♣♦