Pressure exerted on the ground by a person on one foot
Favorites|Homepage
Subscriptions | sitemap
HOME > > Pressure exerted on the ground by a person on one foot

Pressure exerted on the ground by a person on one foot

[From: ] [author: ] [Date: 12-04-04] [Hit: ]
17 N / 0.0346 m^2= 1.......
Calculate the pressure exerted on the ground by a 57 kg person standing on one foot.
Assume that the bottom of the person’s foot is 13 cm wide and 28 cm long.

The answer is 1.5 X 10^4 Pa, but I can't seem to figure out how to get there. Please show steps so I can try to understand. Thanks.

-
Hey Veronica,

This is the equation for pressure: P=F/A. (57*9.81)/(.13)(.28)=1.53e4 Pa. Hope this helps.

David

-
P=F/A,

1Pa=1N/m^2

P=(57kg * 9.81m/s^2)/ (.13m * .28m)

= 559.17 N / 0.0346 m^2
= 1.536 * 10^4 Pa
1
keywords: person,one,exerted,Pressure,on,the,by,foot,ground,Pressure exerted on the ground by a person on one foot
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .