x-y= -5
2x+y= -4
2x+y= -4
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x = y-5 set to x
2(y-5) + y = -4 substitute y-5 for x then solve for y
2y-10 + y = -4
3y = 6
y = 2
x-2 = -5 plug y=2 into the original equation
x = -3
2(y-5) + y = -4 substitute y-5 for x then solve for y
2y-10 + y = -4
3y = 6
y = 2
x-2 = -5 plug y=2 into the original equation
x = -3
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By elimination:
You have x-y=-5 and 2x+y=-4
2x+y=-4
x-y=-5
You can solve this by addition. First column: 2x+x=3x
So we have 3x
Second column: y+(-y)=0 and now you've eliminated your y.
Third column: -4+-5= -9
You're new equation 3x=-9
Divide both sides by 3 and x=-3
You have x-y=-5 and 2x+y=-4
2x+y=-4
x-y=-5
You can solve this by addition. First column: 2x+x=3x
So we have 3x
Second column: y+(-y)=0 and now you've eliminated your y.
Third column: -4+-5= -9
You're new equation 3x=-9
Divide both sides by 3 and x=-3