10^(x+3) = 6^2x i'm stuck halfway through this.....
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10^(x+3) = 6^2x i'm stuck halfway through this.....

[From: ] [author: ] [Date: 12-03-16] [Hit: ]
...5ln(3-x) = 4-you are on the right track,x ≈ 5.x ≈ 0.......
a) so this is how far i have gotten and i cant figure out what to do next...
so you take the log of both sides like this right?

log10^(x+3) = log6^2x ?

and then it will turn into this:

(x+3)log10 = 2xlog6

and then that becomes:

x+3 = 2xlog6 => what to do next is where i am lost : /

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also this problem I don't even know how to begin to start it....

5ln(3-x) = 4

-
you are on the right track,
continue:
x + 3 = 2x log(6)
x - 2x log(6) = -3
x(1 - 2log(6)) = -3 ← distributive property
x = -3 / (1 - 2log(6))
or
x = -3 / (1 - log(36))
now you can calculate
x ≈ 5.3927

5ln(3 - x) = 4
ln(3 - x) = 4/5
3 - x = e^(4/5) ← basic definition of logs
x = 3 - e^(4/5)
or
x ≈ 0.7745

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