We never went over how to do these types of questions, so a little explanation would be appreciated. Thanks in advance.
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If both sides are base 4, you can find the antilog of each side. Raise 4 to the power of each side, which "cancels " the log.
Then 4^ [ log4(2x-1)] = 4^[ log4(16)]
2x-1= 16
2x=17
X=17/2
Hoping this helps!
Then 4^ [ log4(2x-1)] = 4^[ log4(16)]
2x-1= 16
2x=17
X=17/2
Hoping this helps!