log(base t) 5=a and log(base t) 2=b,
express the following in terms of a and b:
log(base t) ∛( 25 (2))
that is a cube root by the way guys.
express the following in terms of a and b:
log(base t) ∛( 25 (2))
that is a cube root by the way guys.
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log[t](5) = a
log[t](2) = b
log[t]((25 * 2)^(1/3)) =>
(1/3) * log[t](25 * 2) =>
(1/3) * (log[t](25) + log[t](2)) =>
(1/3) * (log[t](5^2) + log[t](2)) =>
(1/3) * (2 * log[t](5) + log[t](2)) =>
(1/3) * (2a + b)
log[t](2) = b
log[t]((25 * 2)^(1/3)) =>
(1/3) * log[t](25 * 2) =>
(1/3) * (log[t](25) + log[t](2)) =>
(1/3) * (log[t](5^2) + log[t](2)) =>
(1/3) * (2 * log[t](5) + log[t](2)) =>
(1/3) * (2a + b)