also solve dis question also....
From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to the diameter of the circle, prove that DPAB is equilateral.
10q.. :)
From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to the diameter of the circle, prove that DPAB is equilateral.
10q.. :)
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A person on tour has Rs.360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his expenses by
INCOMPLETE INFORMATION.
From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to the diameter of the circle, prove that PAB is equilateral.
OP = 2R and OA = OB = R whence sin APO = sin BPO = R/2R = 1/2 = sin 30 whence angle APB = 60
also tangents PA = PB hence angles PAB = PBA = [180 -- APB] / 2 = m(180 -- 60)/2 = 60 each
triangle PAB is equilateral. QED.
INCOMPLETE INFORMATION.
From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to the diameter of the circle, prove that PAB is equilateral.
OP = 2R and OA = OB = R whence sin APO = sin BPO = R/2R = 1/2 = sin 30 whence angle APB = 60
also tangents PA = PB hence angles PAB = PBA = [180 -- APB] / 2 = m(180 -- 60)/2 = 60 each
triangle PAB is equilateral. QED.
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Let the no of days be x
360/ x - 360 / ( x+4) = 3
360 ( x+4) - 360x = 3x( x+4)
1440 = 3x^2 +12x
3x^2 + 12x -1440 = 0
x^2 + 4x - 480 = 0
( x- 24) ( x+20) = 0
x = 24 days
ANSWER 20 days
check
360/20 = Rs 18
360/24 = Rs 15
360/ x - 360 / ( x+4) = 3
360 ( x+4) - 360x = 3x( x+4)
1440 = 3x^2 +12x
3x^2 + 12x -1440 = 0
x^2 + 4x - 480 = 0
( x- 24) ( x+20) = 0
x = 24 days
ANSWER 20 days
check
360/20 = Rs 18
360/24 = Rs 15
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Both the questions are incomplete
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He has to extend how long he prays for his immortal soul.
Give your faith back to God, take it back from science.
Give your faith back to God, take it back from science.