How do I find the limit of this? Help, 10 points
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How do I find the limit of this? Help, 10 points

[From: ] [author: ] [Date: 12-01-10] [Hit: ]
(3e^-2x)-1 + 1?x -> ∞ = ?The first term is the equivalent of 1/∞ which is zero,x -> -∞ = ?Now your undoing the negative sign so you get e^∞. So y -> ∞-62 = x-1 for both-x = 62,......
y = 2/3e^-2x + 1 (the 1 is not in the denominator)

lim y
x -> ∞ = ?

lim y
x -> -∞ = ?

y=2/3e^-2x + 1 <-- is it possible to rearrange this into index form and substitute the values in? So,
y = 2.(3e^-2x)-1 + 1?

-
lim y
x -> ∞ = ?
The first term is the equivalent of 1/∞ which is zero, so y -> 1

lim y
x -> -∞ = ?
Now your undoing the negative sign so you get e^∞. So y -> ∞

-
62 = x

-
1 for both

-
x = 62, and No
1
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