I need Help!!! I need the answers by tomorrow!!

Determine the exact value of a and b so that the line E: 3y=ax + 3 is perpendicular to the line F: by=x+2b which in turn is parallel to the line G: y=6x+1

Hi,

If by=x+2b is parallel to the line G: y = 6x+1. then its slope has to be 6 too

by = x + 2b

Divide by b to get y alone.

y = 1/b*x + 2

1/b = 6, then b = 1/6 <==ANSWER

If the line E, 3y=ax + 3, is perpendicular to the line F, then its slope is -1/6.

3y = ax + 3

Divide by 3.

y = (a/3)x + 1

a/3 = -1/6

6a = -3, so a = -1/2

a = -1/2 and b = 1/6 <==ANSWER

I hope that helps!! :-)

by=x+2b => y = x/b+2 is parallel to the line G: y=6x+1 means 1/b=6=>b=1/6

3y=ax + 3 => y=ax/3+1 is perpendicular to the line F: by=x+2b => y=x/b+2 means a/3= -1/b => a=-3*6 =-18

6b=1
b=1/6
y/6=x+1/2
a=-1/6
3y=-x/6+3