Log of 81 to the base 27

pls help

You can rewrite log of 81 to the base of 27 in base 10 by the 'change of base property' as (log81)/(log(27).

log81 = log(3^4) = 4log3 (Using the power rule)
log27 = log(3^3) = 3log3 (Using the power rule)

Therefore, (log81)/(log27) = (4log3)/(3log3) = 4/3

Rewrite log of 81 to the base of 27 in base 10 as (log81)/(log(27).
log81 = log(3^4) = 4log3
log27 = log(3^3) = 3log3

So, (log81)/(log27) = (4log3)/(3log3) = 4/3

Log A base X = Log A base Y / Log X base Y ........Rule

Therefore, log of 81 to the base 27 = log 81 / log 27 = 1.333333333

log of 81 to the base 27 = log81 / log27 =

= log(3^4) / log(3^3) = 4*log3 / 3*log3 =

= 4/3 >==========================< ANSWER

log 81 =log 81 log 27
27 10 / 10
= 4log 3 3 log 3
10 / 10
= 4/3
=1.333

1.33333
http://www.1728.org/logrithm.htm