Solve. 11^(x-1) = 11^(5x-19)
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equating powers: x-1 = 5x-19
4x = 18
x = 4.5
2. 3^(x-5) = 3^2
x-5 = 2
x = 7
3. 4^3x = 4^(2x-2)
3x = 2x-2
x = -2
4x = 18
x = 4.5
2. 3^(x-5) = 3^2
x-5 = 2
x = 7
3. 4^3x = 4^(2x-2)
3x = 2x-2
x = -2
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For 11^(x - 1) to equal 11^(5x - 19), (x - 1) must equal (5x - 19):
x - 1 = 5x - 19
Subtract x from both sides:
-1 = 4x - 19
Add 19 to both sides:
18 = 4x
Divide both sides by 4:
x = 18/4 which reduces to 9/2
x - 1 = 5x - 19
Subtract x from both sides:
-1 = 4x - 19
Add 19 to both sides:
18 = 4x
Divide both sides by 4:
x = 18/4 which reduces to 9/2
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This can be reduced to
x-1 = 5x-19
Subtract x from each side.
-1 = 4x-19
Add 19 to each side
4x = 18
x = 4.5
x-1 = 5x-19
Subtract x from each side.
-1 = 4x-19
Add 19 to each side
4x = 18
x = 4.5
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1. x = 4.50
2. x = 8
3. x = -0.333
2. x = 8
3. x = -0.333
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Observing index laws:
x-1 = 5x-19
x-1 = 5x-19