What is the pH and pOH of 4.3x10^-2

Thanks!

There is not enough information to answer this question. If you mean "What is the pH and pOH of a solution which has an H+ concentration of 4.3x10^-2", the pH would be 1.37 and the pOH would be 14-1.37 or 12.6.
pH=-log(concentration of H+), or 14-pOH
pOH=-log(concentration of OH-), or 14-pH

Using the figure as H+ions the pH is 1.27 pOH = 14.00 - 1.27 = 12.73