I need help on a homework question...I need to write the transformed equation for y = 7ƒ(-1/6(x-1)) + 1,
ƒ(x) = x^2
Could someone help me or explain how it's done for this function??
Thank you))
ƒ(x) = x^2
Could someone help me or explain how it's done for this function??
Thank you))
-
ƒ(x) = x^2
7f(x) = 7(x^2)
7ƒ(-1/6(x-1)) = 7( (-1/6(x-1))^2 )
7ƒ(-1/6(x-1)) + 1 = 7( (-1/6(x-1))^2 ) + 1
y = 7( (-1/6(x-1))^2 ) + 1
y = [ (-7/6)(x-1)^2 ] + 1
7f(x) = 7(x^2)
7ƒ(-1/6(x-1)) = 7( (-1/6(x-1))^2 )
7ƒ(-1/6(x-1)) + 1 = 7( (-1/6(x-1))^2 ) + 1
y = 7( (-1/6(x-1))^2 ) + 1
y = [ (-7/6)(x-1)^2 ] + 1