find the term void of x in the expansion of ( x + 1/x)^2n ; x РЅа 0
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I'm guessing that it is asking for the term that does not include x.It would be when 2n-r=r=n
2nCn*(x)^n*(1/x)^n=2nCn=(2n)!/(n!)^2
2nCn*(x)^n*(1/x)^n=2nCn=(2n)!/(n!)^2
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idk the meaning of void :D
bt i hope its independent of x :D
so first of all rite the general term of a binomial expansion put d values like dis
T(r+1) = nCr (A)^n-r (B)^r
T(r+1) = 2nCr (x)^2n-r (1/x)^r
T(r+1) = 2nCr (x)^2n-r (x^-1)^r [as 1/x can be written as x^-1 ]
T(r+1)= 2nCr (x)^2n-r-r
so now just consider x !
2n-r-r =0
because we want d term in wich x's power (exponent) should be zero !
so n=r is the term independent of x :)
bt i hope its independent of x :D
so first of all rite the general term of a binomial expansion put d values like dis
T(r+1) = nCr (A)^n-r (B)^r
T(r+1) = 2nCr (x)^2n-r (1/x)^r
T(r+1) = 2nCr (x)^2n-r (x^-1)^r [as 1/x can be written as x^-1 ]
T(r+1)= 2nCr (x)^2n-r-r
so now just consider x !
2n-r-r =0
because we want d term in wich x's power (exponent) should be zero !
so n=r is the term independent of x :)
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well if n = 1, the expansion would be x^2 + 2 + 1 / (x^2).
I'm not sure what the question is asking. This seems like a question with a typo or an advanced math question.
I'm not sure what the question is asking. This seems like a question with a typo or an advanced math question.