Probability question!!!

In a gambling game, players pay an entry fee of £1.
They then throw a die until it shows 6.
If only one throw is needed, the player receives £3.
If two throws are needed, the player receives £2.
If three throws are needed, the player gets his or her entry fee back; otherwise the £1 is lost.
What is the probability that a player:
1. gets the £1 entry fee back
2. loses the entry fee

I really am confused on what to do here
I keep getting the wrong answer

Your help is appreciated
Thanks! :)

If the player gets it back, this means the first throw is not a six, the second throw is not a six, and the third throw is a six.

This happens with probability 5/6 * 5/6 * 1/6 = 25/216

If the player loses it entirely, then the first, second, and third throws are not sixes.

This happens with probability 5/6 * 5/6 * 5/6 = 125/216

1)
p(gets fee back) = p(first roll not equal to 6) * p(second roll not equal to 6) * p(third roll equals 6)
p(gets fee back) = 5/6 * 5/6 * 1/6 = 25/216

2)
p(loses fee) = p(first roll not equal to 6) * p(second roll not equal to 6) * p(third roll not equal to 6)
p(loses fee) = 5/6 * 5/6 * 5/6 = 125/216

To succeed You need to find something to hold on to, something to motivate you, something to inspire you

1. its 11/18
2. its 5/6