Calculus: Work Integration
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Calculus: Work Integration

[From: ] [author: ] [Date: 11-12-13] [Hit: ]
500 foot-pounds.Hope this helped.......
A 1600-lb elevator is suspended by a 200-ft cable that weighs 10 lb/ft. How much work is required to raise the elevator from the basement to the third floor, a distance of 30 ft?

Please show all steps, thank you.

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Since you're going to life the elevator 30 feet, the bounds will be from 0 to 30. The weight of the cable as you lift it up is given by 10(200 - x), where x is the number of feet lifted. Note that the weight of the elevator is never going to change. Therefore the work done is given by:

30
∫ 1,600 + 10(200 - x) dx = 1,600x + 2,000x - 5x^2 [0 , 30]
0

1,600(30) + 2,000(30) - 5(30^2) =
48,000 + 60,000 - 4,500 = 103,500 foot-pounds.


Hope this helped.
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