The length of a rectangle is 3 more than twice the width. If the perimeter is 54 inches, what is the width of the rectangle?
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Its 8. 8*2 is 16. 16*2 is 32. 16+32 is 48. 48+6 is 54.
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Let w= width of the rectangle
2w+3= length of the rectangle
Perimeter = length + length + width + width
Can you solve this?
2w+3= length of the rectangle
Perimeter = length + length + width + width
Can you solve this?
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54 divided by 10 times 2 which i believe equals 10.8