Completely lost on this calculus optimization problem. Please help
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Completely lost on this calculus optimization problem. Please help

[From: ] [author: ] [Date: 11-12-02] [Hit: ]
let x = 35 then find value of h that maximizes θ√(45h + 2025) = 3545h + 2025 = 122545h = −800h = −17.78You cannot erect sign of any height above building so that best view is 35 feet from building.......

When h = 10, θ is maximized when x = √(45*10 + 2025) = √2475 = 49.7 ft

Good, our result matches what we were expecting!

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From above, we found that θ is maximized when x = √(45h + 2025) feet

To determine the height of the new sign so that the best view occurs when the observer is 60 feet from the building, let x = 60 then find value of h that maximizes θ

√(45h + 2025) = 60
45h + 2025 = 3600
45h = 1575
h = 35

Sign should be 35 feet tall for best view at 60 feet from building.

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To determine the height of the new sign so that the best view occurs when the observer is 35 feet from the building, let x = 35 then find value of h that maximizes θ

√(45h + 2025) = 35
45h + 2025 = 1225
45h = −800
h = −17.78

You cannot erect sign of any height above building so that best view is 35 feet from building. What h < 0 means, however, is that you CAN erect a sign hanging 17.78 ft from top of building (instead of on top of building) to get best view at 35 feet from building.

Mαthmφm
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