∫∫ sqrt(1-y²)dA , R is the triangle with vertices (0,0), (1,0) and (1,1)
R
I got an answer of 1/3 by setting my limits to:
0≤x≤y and 0≤y≤1
Is this correct?
R
I got an answer of 1/3 by setting my limits to:
0≤x≤y and 0≤y≤1
Is this correct?
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your limits are correct. You could have also integrated from 0≤y≤x and 0≤x≤1 but based on your understanding you probably already knew that.