f(x) = √(x/(π-x)) i.e is the square root of x over pi - x
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X is an element of the Real numbers but x cannot be greater than or equal to pi nor can it be less than 0
Reason
if it is equal to pi.. the denominator will be 0.... fraction cannot have 0 as a denominator...or else it will be infinity
if it is greater than pi, the denominator will be negative and the numerator will be positive... you cannot have the square root of a negative number
if x is less than 0 the numerator will be negative and the denominator will be positive... again, you cannot have the square root of a negative number
ANSWER?
so that means that the DOMAIN is 0<=x
or [0,pi)
Reason
if it is equal to pi.. the denominator will be 0.... fraction cannot have 0 as a denominator...or else it will be infinity
if it is greater than pi, the denominator will be negative and the numerator will be positive... you cannot have the square root of a negative number
if x is less than 0 the numerator will be negative and the denominator will be positive... again, you cannot have the square root of a negative number
ANSWER?
so that means that the DOMAIN is 0<=x
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Notice that we have two limitations 1)The equation is inside a square root meaning the number inside the root cannot be negative 2) The denominator cannot equal zero, therefore pi cannot be a solution .
So, the domain is: [0,pi) The solution includes numbers from 0 to pi, but not including pi.
So, the domain is: [0,pi) The solution includes numbers from 0 to pi, but not including pi.
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x cannot equal pi or zero, i believe. and x<0