Find a and b : If |x - 3| < 7, then a < x - 2 < b
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Find a and b : If |x - 3| < 7, then a < x - 2 < b

[From: ] [author: ] [Date: 11-09-20] [Hit: ]
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|x - 3| < 7
-7 -7+1 -6
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|x - 3| < 7
(x - 3)² < 49 ... That operation was allowed because both sides were non-negative.
x² - 6x + 9 < 49
x² - 6x - 40 < 0
(x + 4)(x - 10) < 0
-4 < x < 10
a = -4, b = 10
1
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