Solve this Math Question 2

1+y×4+(6÷2×3)×62×(y×y)
If y=3, what is the answer to the equation?

1+y×4+(6÷2×3)×62×(y×y)= 1+ 3x4+3x3x62x (3x3)
=1+ 12 +81x62
=13 + 5022
=5035

Done!

1+3*4+((6)/(2)*3)*62*(3*3)

Reduce the expression (6)/(2) by removing a factor of 2 from the numerator and denominator.
1+3*4+(3*3)*62*(3*3)

Multiply 3 by 3 to get 9.
1+3*4+(9)*62*(3*3)

Multiply 3 by 3 to get 9.
1+3*4+(9)*62*(9)

Multiply 3 by 4 to get 12.
1+12+(9)*62*(9)

Multiply all the factors separated by a * in 1+3*4+(9)*62*(9).
1+12+62(9)(9)

Multiply 9 by 9 to get 81.
1+12+62(81)

Multiply 62 by each term inside the parentheses.
1+12+5022

Add 12 to 1 to get 13.
13+5022

Add 5022 to 13 to get 5035.
5035

Given y=3;1+y*4+(6/2*3)*62*(y*y)the formula is to work out the bracket first then divide then multiply then add and at last subtract.So your answer is 561.

i did it and i got 576....maybe its right maybe it is wrong, but i hope it is right, i think i did it correctly, glad i could try to help you

1+3×4+(6÷2×3)×62×(3×3)
1+3×4+(3×3)×62×(3×3)
1+3×4+(9)×62×(9)
16+(9)×62×(9)
16+9×62×9
25×62×9
1550×9
13,950

5035 is the correct answer