2)which system of equations represents a pir of parallel lines and no solution:
i know the answer is:
3x-3y=6
2x-5y=-8
Linear equations that represent parallel lines have the same slope. You need to get y by itself in both equations to make slope-intercept form.
3)The admission fee of a theatre is $2.50 for adults and $1.25 for children. O a certain day, 700 people went to the theatre and $1375 was collected. Using equation below, determine how many children and how many adults attended the show.
2.5x+1.25y=1375
x+y=700
how do i do this?
Get y by itself in both equations and then make the equations equal to each other.
4) What is the simplified form of (square root sign will be used as **) *xy(3 power)* x *x(3 power)y*?
If I understand correctly what you mean, you need to multiply the xs and ys together to get *x(power of 5)y(power of 4). Next, you must simplify the radicals by making the x the square root of x^4 and the square root of x, and y the square root of y^4, making it x^2 times the square root of x times y^2, because x^2 and y^2 are the square roots of x^4 and y^4 but x has no square root, so it stays x*. Sorry if that was hard to understand, it's hard to explain via the computer.
5) given the equation: y=3x-4 which equation would give you a system of equations with perpendicular lines and one solution?
The answer is: y= -1/3x + 3
how do i find this out?
The perpendicular line of an equation is its negative slope reversed. For example, any equation with a slope of 3x would be perpendicular to your equations.
5)Given the equation: y=3x-5 which equation forms a system of equations that (2,1) is the only solution?
The answer is: 2x-3y=1
how do i figure this out?
For this one, you were probably given multiple choice, right? You just need to sub the points in in the equations you are given, with 2 substituting x and 1 substituting y, so that it turns out like this:
2x-3y=1
4-3=1
1=1 --- the equation works out
6)the value (3 power)*90* is between what 2 integers?
how do i figure this out?
I don't really understand what you mean? Could you please phrase the equation differently?