If x, x+3, and y are the lengths of the sides of a triangle, then
(blank) < y < (blank)
(blank) < y < (blank)
-
u can use the triangular inequalities to solve the problem.
one is, sum of two sides is greater than the the third side.
the other one is difference of two sides is lesser than the third side.
since the inequality is based on "y", let that be the third side..
x, x+3 be the other two sides
hence, the diff of two sides gives 3 i.e ( x +3 - x)
and sum of the two sides give, 2x + 3 !!
this gives u the answer... :)
one is, sum of two sides is greater than the the third side.
the other one is difference of two sides is lesser than the third side.
since the inequality is based on "y", let that be the third side..
x, x+3 be the other two sides
hence, the diff of two sides gives 3 i.e ( x +3 - x)
and sum of the two sides give, 2x + 3 !!
this gives u the answer... :)
-
I believe it would be: x< y< x+3
I think this because y is obviously in the middle of things. The 'x' variable must be smaller than 'y' because x+3 is larger than 'x'. The reason x+3 is larger than x is because you add 3 to it.
I hope this helps you out. :)
I think this because y is obviously in the middle of things. The 'x' variable must be smaller than 'y' because x+3 is larger than 'x'. The reason x+3 is larger than x is because you add 3 to it.
I hope this helps you out. :)
-
x
x+3 is bigger than x hence...
x+3 is bigger than x hence...