i have another hard math problem.....and anyway thanx for all your previous answers, they rlly helped me on my homework.... i dont know how to approach this equation...
(3n+3)! / (n-1)! = 126
(3n+3)! / (n-1)! = 126
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No solution
(3n+3)! not equal to 3(n+1)! but I supposed you modified the problem
Then I supposed this problem
3(n+1)!/(n-1) = 126
n(n+1) = 42
then n = 6 ( because n = - 7 not allowed)
(3n+3)! not equal to 3(n+1)! but I supposed you modified the problem
Then I supposed this problem
3(n+1)!/(n-1) = 126
n(n+1) = 42
then n = 6 ( because n = - 7 not allowed)
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whatever n is, the left side will end up as a product of consecutive integers.
126 = 3•6•7, which is as close as you can get to consecutive, so no solution.
126 = 3•6•7, which is as close as you can get to consecutive, so no solution.
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NEED TO PUT IT IN A REAL FORM!!!