Quick math problem! 10 points to BEST answer 1st!! :)

Consider the rectangle PQRS with vertices at P (-1, -1), Q (7, -1), R (7, 3) and S (-1, 3). For each step, draw the newly transformed shape and record the vertices.

You have translated rectangle PQRS down 2 units and left 3 units. Afterward you rotated the rectangle 90 degrees clockwise.

Now translate PQRS up 1 unit and right 3 units. What are the new coordinates?

~I dont get how to solve this at ALL :( i tried and failed

Left 3 units subtracts 3 from each x coordinate. Down 2 units subtracts 2 from each y coordinate. This takes the rectangle to (-4, -3), (4, -3), (4, 1), (-4, 1).

The centre of rotation isn't given so I'll assume that it is the origin. A clockwise rotation of a point (x, y) takes it to (y, -x) so the coordinates above move to
(-3, 4), (-3, -4), (1, -4), (1, 4).

Moving right 3 units adds 3 to all the x coordinates. Moving up 1 unit adds 1 to all the y coordinates. The rectangle ends at (0, 5), (0, -3), (4, -3), (4, 5).

PQRS = {(-1, -1), (7, -1), (7, 3), (-1, 3)}

Down 2 units and left 3 units is (x,y) -> (x-3, y-2)
P'Q'R'S' = {(-4, -3), (4, -3), (4, 1), (-4, 1)}

Rotate 90 degrees clockwise is (x, y) -> (-y, x)
P''Q''R''S'' ={(-3,4), (-3,-4), (1,-4), (1,4)}

translate up 1 unit and right 3 units is (x, y) -> (x+3, y+1)
P'''Q'''R'''S''' = {(0, 5), (0, -3), (4, -3), (4, 5)}