A quick problem for 10 POINTS to best answer 1st!:) go go gooo!!

Consider the rectangle PQRS with vertices at P (-1, -1), Q (7, -1), R (7, 3) and S (-1, 3). For each step, draw the newly transformed shape and record the vertices.

You have translated rectangle PQRS down 2 units and left 3 units.

Now, assuming the axis of rotation of PQRS is at the center of the shape, rotate the rectangle 90 degrees clockwise. What are the new coordinates?

You will have to do the drawings
Original vertices P (-1, -1), Q (7, -1), R (7, 3) and S (-1, 3)
Reducing x by 3 and y by 2
Second vertices P (-4, -3), Q (4, -3), R (4, 1) and S (-4, 1)
Rectangle at this stage is wider than tall, (8 wide by 4 tall)

Centre now at C (0, -1) Midpoint of PS is 4 to the left at D (-4, -1)

After clockwise rotation by 90 degrees, the rectangle is
taller than wide, (4 wide by 8 tall).
Midpoint of PS goes to 4 above C at (0, 3)
Top along y = 3, bottom along y = -5
Left side along x = -2, right side along x = +2,

Final vertices P (-2, 3), Q (-2, -5), R (2, -5) and S (2, 3)

Regards - Ian

P (-2,3) Q(-2,-5) R(2,-5) S(2,3)

Math homework?