log base 3 (x+4) + log base 3 (x-2) = 3
i know since it's adding two things with the same base it would become:
log base 3 (x+4)(x-2) = 3
but how would you solve from here?
i know since it's adding two things with the same base it would become:
log base 3 (x+4)(x-2) = 3
but how would you solve from here?
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use identity, a^(log base a of x) = x
log_3 (x+4)(x-2) = 3
(x + 4)(x - 2) = 3^3
x² + 2x - 8 = 27
x² + 2x - 35 = 0
(x + 7)(x - 5) = 0
can't use x = -7 since that would make the logs undefined, so
x = 5
log_3 (x+4)(x-2) = 3
(x + 4)(x - 2) = 3^3
x² + 2x - 8 = 27
x² + 2x - 35 = 0
(x + 7)(x - 5) = 0
can't use x = -7 since that would make the logs undefined, so
x = 5