Maths HELP please!! Can someone solve this
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Maths HELP please!! Can someone solve this

[From: ] [author: ] [Date: 11-05-22] [Hit: ]
Therefore, our answer is correct.x=$ 19.The cost of the toy is $19.......
A bath toy bought for $x is sold for $24, making x% profit. What was the cost of the toy?

thankyou very much

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% means per 100 so x% = x / 100

(24 - x) / x = percent profit = x% = x / 100

(24 - x) / x = x / 100

2400 - 100x = x^2

x^2 + 100x - 2400 = 0

Solve for the roots of the quadratic equation.

(x + 120)(x - 20) = 0

x = -120 , x = 20

Since the cost cannot be negative, we disregard x = -120. So we get x = 20. The cost of the toy is $20.

Let us check our answer. We'll substitute 20 for x on both sides of our original equation.

($24 - $20) / $20 = 4 / 20 = 1 / 5 = 0.2

20% = 20 / 100 = 2 / 10 = 1 / 5 = 0.2

Therefore, our answer is correct.

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x+x/100*x = 24
x^2 + 100x-2400 = 0
x = (-100+/-sqrt(10000+9600))/2 = (-100+/-140)/2
x = -120 no sense
x = 20
Proving
20+20%*2= 24
profit 4/20 = 20%
Cost of toy $20

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profit percentage =[(Selling price-Buying price)/Selling price] *100

x = [(24-x)/24]*100
24x =2400-100x
124x=2400
x=$ 19.35
The cost of the toy is $19.35
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