This conic has a directrix at y = 4, an eccentricity of 1/4, and its focus is stationed at the pole (0,0).
I got r = 4/(4+sintheta)
Did you get that?
I got r = 4/(4+sintheta)
Did you get that?
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you got it right
r = ed /(1 + esin(θ))
here e = 1/4, d = 4
r = (1/4)4 /(1 + (1/4)sin(θ))
r = 1 /(4 + sin(θ))/4
r = 4/(4 + sin(θ))
r = ed /(1 + esin(θ))
here e = 1/4, d = 4
r = (1/4)4 /(1 + (1/4)sin(θ))
r = 1 /(4 + sin(θ))/4
r = 4/(4 + sin(θ))