6
S (4/3)^n-1
n=1
thank you guys :)
S (4/3)^n-1
n=1
thank you guys :)
-
6
S (4/3)^n-1
n=1
= 1[(4/3)^6 -- 1] /[(4/3) -- 1]
= [4^6 -- 3^6] / 3^5
= 13 208/243
S (4/3)^n-1
n=1
= 1[(4/3)^6 -- 1] /[(4/3) -- 1]
= [4^6 -- 3^6] / 3^5
= 13 208/243