URGENT! Mass in g of C3H7Cl produced if 400 g of propane react w/ excess Cl gas according to equation below

Mass in g of 1-chloropropane (C3H7Cl) produced if 400 grams of propane react with excess Cl gas according to the equation C3H8 + Cl2 --> C3H7Cl + HCl?

PLEASE ANSWER SOON.

C3H8 + Cl2 → C3H7Cl + HCl

(400 g C3H8) / (44.0959 g/mol) x (1/1) x (78.5412 g/mol) = 712 g C3H7Cl

I'm making no assertion about how much 1-chloropropane is produced, since 2-chloropropane is also possible. There will be 712 g in total of chorinated propanes with molecular formula C3H7Cl.