The base of a triangle is 2x + 2m and the are is 2x^2 - x - 3m^2 . Find the height of the triangle. ( Area = 1/2bh)
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Let 2x + 2 denotes the base and 2x² - x - 3 denotes the area. This gives us:
2x² - x - 3 = ½(2x + 2)h
By factoring 2x + 2, we have:
2x² - x - 3 = ½ * 2(x + 1)h
Reduce the common factors of 2 to get:
2x² - x - 3 = (x + 1)h
Then, factor 2x² - x - 3 to get:
(2x - 3)(x + 1) = (x + 1)h
Finally, by comparing both sides, we can tell that h = 2x - 3.
I hope this helps!
2x² - x - 3 = ½(2x + 2)h
By factoring 2x + 2, we have:
2x² - x - 3 = ½ * 2(x + 1)h
Reduce the common factors of 2 to get:
2x² - x - 3 = (x + 1)h
Then, factor 2x² - x - 3 to get:
(2x - 3)(x + 1) = (x + 1)h
Finally, by comparing both sides, we can tell that h = 2x - 3.
I hope this helps!