Estimate each answer. Then tell which answer choice(s) you can eliminate. (Please give 6th grade answers)
1. What value is closest to the area of a circle with a 3-inch radius?
A. 9 square inches B. 19 square inches C. 28 square inches D. 113 square inches
2. To the nearest inch, find the circumference of a circle with a 3-inch radius.
F. 9 inches G. 19 inches H. 28 inches I. 113 inches
3. To the nearest tenth, how many more square inches of pizza are in a
pizza with a 14-inch diameter than in a pizza with a 12-inch diameter?
A. 13 square inches B. 21.3 square inches C. 40.8 square inches D. 163.3 square inches
1. What value is closest to the area of a circle with a 3-inch radius?
A. 9 square inches B. 19 square inches C. 28 square inches D. 113 square inches
2. To the nearest inch, find the circumference of a circle with a 3-inch radius.
F. 9 inches G. 19 inches H. 28 inches I. 113 inches
3. To the nearest tenth, how many more square inches of pizza are in a
pizza with a 14-inch diameter than in a pizza with a 12-inch diameter?
A. 13 square inches B. 21.3 square inches C. 40.8 square inches D. 163.3 square inches
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1. Formula for area of a circle is πr². In this case it will be π3². So then you wort it out (or not) and you get 9π and pi is 3.14 something. The closest would be C.
2.The formula for circumference is 2πr, so 2π3. Worked out would be 6π. The answer would be G.
3.For this you would have to find the area for both and then subtract the area from the 12in pizza from the area of the 14in pizza. π7² - π6².-------->153.9 - 113 (instead of using pi i just did the simple 3.14 which is close enough) The answer is C.
EDIT:After I checked other user submitted answers, AJ Archer is wrong on the last question, he multiplied the diameters instead of the radius, fail.
2.The formula for circumference is 2πr, so 2π3. Worked out would be 6π. The answer would be G.
3.For this you would have to find the area for both and then subtract the area from the 12in pizza from the area of the 14in pizza. π7² - π6².-------->153.9 - 113 (instead of using pi i just did the simple 3.14 which is close enough) The answer is C.
EDIT:After I checked other user submitted answers, AJ Archer is wrong on the last question, he multiplied the diameters instead of the radius, fail.
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Are you cheating on your math homework?
1. 3.14(pi)*radius squared (radius times radius)
2. Diameter (two times radius) * 3.14 (pi)
3. Find the area of the 14 inch DIAMETER pizza (3.14*RADIUS squared) - (3.14*radius squared)
I can help you check your answers if you want.
1. 3.14(pi)*radius squared (radius times radius)
2. Diameter (two times radius) * 3.14 (pi)
3. Find the area of the 14 inch DIAMETER pizza (3.14*RADIUS squared) - (3.14*radius squared)
I can help you check your answers if you want.
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1. C
A = pi * r^2
A = 3.14 * 3^2
A = 3.14 * 9
A = 28.26
2. G
C = 2 * pi * r
C = 2 * 3.14 * 3
C = 6 * 3.14
C = 18.84
3. D
For the first pizza:
A = pi * r^2
A = 3.14 * 196
A = 615.44
For the second pizza:
A = pi * r^2
A = 3.14 * 144
A = 452.16
Just subtract:
615.44 - 452.16 = 163.28
A = pi * r^2
A = 3.14 * 3^2
A = 3.14 * 9
A = 28.26
2. G
C = 2 * pi * r
C = 2 * 3.14 * 3
C = 6 * 3.14
C = 18.84
3. D
For the first pizza:
A = pi * r^2
A = 3.14 * 196
A = 615.44
For the second pizza:
A = pi * r^2
A = 3.14 * 144
A = 452.16
Just subtract:
615.44 - 452.16 = 163.28
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1 C
2 G
3 C
2 G
3 C